computer network previous question papers

C-05-CM-401

456

BOARD DIPLOMA EXAMINATION, (C-05)

OCT /NOV-2011

DCME.-IV SEMESTER EXAMINATION

COMPUTER NETWORKS

TIME: 3 Hours]                                                                     [Total Marks :100]

PART   - A

INSTRUCTION:  (1) ANSWER ALL QUESTION AND EACH QUESTION

                                           CARRIES FOUR MARKS

                    (2)  ANSWER SHOULD BE BRIEF AND   STRAIGHT      TO  THE POINT AND SHALL NOT EXEED FIVE SIMPLE SENTENCES

1.     List any four hardware components of a typical network.

2.     What is meant by network topology? Write the names of any three network topologies.

3.     Explain the difference between single attachment station(SAS) and Dual Attachment Station (DAS) with reference to FDDI LANs

4.     Explain briefly about HTTP protocol.

5.     What are the components of an IP address?

6.     What are the advantages of NETBEUI over IP and IPX?

7.     Explain the following with reference to Integrated Services digital Netwrok (ISDN). (A) Basic Rate Interface (BRI) (b) Primary rate Interface (PRI)

8.     List out the names of various WAN protocols.

9.     Write about the Fault Management component of ISO network management model.

10.  What are the SNMP manager and SNMP agent?

Instructions :    (1) Answer any five questions and each question carries twelve marks.

                  (2) The answers should be comprehensive and the criteria for valuation   is the content but not the length of the answer.

11.   Explain the OSI reference model with a neat sketch indicating the function of each layer.

12.   Write briefly about the following: (a) wireless LANs (b) FTP.

13.   Compare various transmission media.

14.   Write about IP subnetting.

15.   Write about variable length subnet Mask (VLSM).

16.   Explain the following WAN connectivity options. (a)microwave (b) radio.

17.   Write about virtual private networks (VPNs).

18.   What is the need for network management? Explain the tasks involved in managing a network.

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C-09-CM-401

456

BOARD   DIPLOMA   EXAMINATION,   (C-05)

OCTOER/NOVEMBER 2011

D.C.M.E   -   IV SEMISTER EXAMINATION

COMPUTER NETWORKS

TIME: 3 Hours]                                                                     [Total Marks :80]

PART   - A                                          10*4=40

Instruction:  (1) answer all question and each question

                                           carries FOUR marks

                    (2)  answer should be brief and   straight      to  the point and shall not exceed five simple sentences

1.      List any four hardware components of a typical network.

2.      What is meant by network topology? Write the names of any three network topologies.

3.      Explain the difference between single attachment station(SAS) and Dual Attachment Station(DAS) with reference to FDDI LANs.

4.      Explain briefly about HTTP protocol.

5.      What are the components of an IP address?

6.      What are the advantages of NETBEUI over IP and IPX?

7.      Explain the following with reference to Integrated Services Digital Network(ISDN). (a) Basic Rate Interface(BRI) (b) Primary Rate Interface(PRI)

8.      List out the names of various WAN protocols.

9.      Write about the Fault Management component of ISO NETWORK management model.

10.  What are the SNMP manager and SNMP agent?

 PART- B                                    5*10=50

Instructions: (1) Answer any five questions and each question carries ten marks. (2) The answers should be comprehensive and the criteria for valuation is the content but not the length of the answer.

  

11. Explain the OSI reference model with a neat sketch indicating the function of each layer.

12. Write briefly about the following: (a) Wireless LAN’s (b) FTP.

13. Compare various transmission media.

14. Write about IP subnetting.

15. Write about variable length subnet Mask(VLSM).

16. Explain the following WAN connectivity options. (a) Microwave (b) Radio

17. Write about virtual Private Netwroks(VPNs).

18. What is the need for netwrok management? Explain the tasks involved in managing a network.

Explain serial and parallel communication

Explain serial and parallel communication

Serial and Parallel Communication

SERIAL

Serial communication is the method of transferring one bit at a time
through a medium.


Serial transmission is much more common, particularly over longer distances. It is generally much cheaper as only a single channel between sender and receiver is required, eg: The seven bits (plus one parity check bit) making up an American Standard Code for Information Interchange (ASCII) character are transmitted serially in sequence by the sender and are reassembled into the character by the receiver. A common example of a serial interface
standard is Recommended Standard 232 (RS232).


Three things should be considered when discussing serial communications and the equipment to carry this out:

Electrical standards associated with the interface
Mechanical standards associated with the interface
Standards organisations involved

Data transmission may take place in one direction only or it may be bi-directional. There are 3 groups into which the channel can be classified:



asynchronous transmission:
With asynchronous transmission signal timing is not required; signals are sent in an agreed pattern of bits and if both ends are agreed on the pattern then communication can take place.

Bits are grouped together and consist of both data and control bits. If the signal is not synchronised the receiver will not be able to distinguish when the next group of bits will arrive. To overcome this the data is preceded by a start bit, usually binary 0, the byte is then sent and a stop bit or bits are added to the end. Each byte to be sent now incorporates extra control data. In addition to the control data small gaps are inserted between each chunk to distinguish each group.

In asynchronous transmission each bit remains timed in the usual way. Therefore, at bit level the transmission is still synchronous (timed). However, the asynchronous transmission is applied at byte level, once the receiver realises that there is a chunk of incoming data timing (synchronisation) takes place for the chunk of data.

Asynchronous transmission is relatively slow due to the increased number of bits and gaps. It is a cheap and effective form of serial transmission and is particularly suited for low speed connections such as keyboard and mouse.

One example of asynchronous transfer is Asynchronous Transfer Mode (ATM) switching. ATM allows voice, data and video to be transmitted in fixed length cells of 53 bytes.





PARALLEL

Parallel communication is the method of transferring blocks,
eg: BYTEs, of data at the same time.

Parallel transmission requires a separate channel for each bit to be transmitted. Therefore, to transfer a byte, eight channels will be required between the sender and receiver. Added to these eight are additional channels that are needed for control information and if full duplex communication is required then even more channels would be required. Parallel transmission is rare, other than for very short distances, eg: within a computer, eg: data bus, or between a computer and a printer, eg: Centronics printer interface.

1.6 define channel capacity. 
ans:
Transmission Modes
ans:
Simplex

Half Duplex

Full Duplex

Baud and Data Rates

Distinguish between Digital and Analog Transmission

Distinguish between Digital and Analog Transmission

Need of Data communication and Networking?

3. Need of Data communication and Networking?
ans:

• Signal generation
• Interfacing
• Synchronization
• Exchange Management
• Transmission System
• Error Detection and Correction
• Flow Control
• Addressing
• Routing
• Message formatting
• Distributed data base
• Cheap and efficient data transmission over long distances
• Provides robust communication infrastructure 
• Enables e-commerce, e-governance, e-services

Signal generation: If you want to send the data to some other location , our device should generate and receive the signal.

Interface: A device must have interface with the transmission system in order to communicate.

Synchronization: whenever two or more devices are sending the data at a time to targeted device, one device should wait, until first divice ends the signal so receiver should know when the transmission of data starts , when it ends.

Exchange Management: for data transmission exchange the resource should be done in efficient manner

Message Formatting: which explains the data can be sent on which format i.e audio or video, text etc

Transmission System Utilisation: it refers to the need to make efficient use of transmission channel, which are generally shared by many communicating devices, various techniques (multi-plexing) are available to allocate the total capacity of a transmission channel among connected devices. Care should be taken to avoid probable

Error Detection and Correction: It is used to correct the data while transmitting from one computer to another computer. It is may not important in case of telephonic conversation.

Flow control: If there is a flow control mechanism is there between the two communication devices, data transmission generates faster than the receiver.

Addressing: when more than two devices share a transmitting facility, source device and destination device should have the identity(or address)

Routing: the routing requires to transmit the data destination

Data communication & networking is needed because it offers cheapest means of data services, allows to share resources and so on.

• Distributed data base
• Cheap and efficient data transmission over long distances
• Provides robust communication infrastructure 
• Enables e-commerce, e-governance, e-services

Data communication & networking is needed because it offers cheapest means of data services, allows to share  resources and so on.

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OCTOBER/NOVEMBER-2011 (C-09)

C-09-CM-403
3453

BOARD DIPLOMA EXAMINATION, (C-09)

OCTOBER/NOVEMBER-2011

DCME VI SEMESTER EXAMINATION

COMPUTER HARDWARE & NETWORKING

Time : 3 Hours]                                                               [Total Marks: 80

PART-A    3*10=30

Instructions: (1) Answer all questions and each question caries three marks. (2) Answers should be brief and straight to t the point and shall not exceed five simple sentences.

1.     List the components inside the computer.

2.     Write the features of chipset

3.     Define form factor of system board

4.     Write short notes on RDRAM

5.     Write short notes on RIMM.

6.     What is a surge protection

7.     List different trouble shooting tools

8.     State the need for networking

9.     Write about coaxial cable.

10. What are the components of IP addressing

PART-B                                              10*5=50

Instructions: (1) Answer any five questions and each question caries ten marks. (2) The Answers should be comprehensive and criteria for valuation is the Content but not the length of the answer.

11. Explain the steps in booting process

12. (a) Explain about ISA. (b) Explain about MCA.

13. (a) Explain about AGP. (b)Explain about CMOS setup.

14. Explain different functional units in CD-ROM drive.

15. Explain the trouble shooting procedure of system board.

16. Explain monitor trouble shooting.

17. Explain the classification of Networks according to their size.

18. Write short notes on: (a) Reapeaters (b) Hubs (c) Switches

1.6)Know the different types of RAMs in use?

RAM: (Random Access Memory).

1)    RAM is the main memory of the computer (primary memory)

2)    RAM is used as random access memory.

3)    RAM is used as temporary working space of the CUP and other components of the PC .

4)     It holds the operating system, programs, and data that are currently in use.

5)    Temporary memory stored on chips, such as RAM which can be installed on SIMM, DIMM, and RIMM slots inside the computer.

6)     The information stored in RAM is volatile.

7)     RAM speed is measured in ns (anon seconds).

   Types:

                                     

STATIC RAM:

Ø     Static ram stores date in electronic circuit called FlipFlop.

Ø     It uses 6 Transistors in order to store in memory all.

Ø     It stores the data till the power is on.

Ø     S-RAM normally reserved for speed. Critical functions such as system cache.

Ø     It is about 4-5 times faster than D-RAM.

DYNAMIC RAM:

Ø     D-RAM is used as the main or system memory of a pc that that stores the operating system application programmes and data while they are running.

Ø     It uses one transistor and one capacitor for a memory call.

Ø     Comparing to S-RAM data access is slow.

Ø     It stores the date only for few milliseconds after it has to be refreshed and charge gain. 

   

  

FPM RAM :( Fast Page Mode)

1)     Normally D-RAM required a row and column address to be sent for each access to memory cell.

2)    FPM offers speed improvements by sending the row address just for money access to memory.

EXTENDED DATA OUTPUT D-RAM:- (EDO D-RAM)

Ø     EDO D-RAM works similarly to FPM  D-RAM

Ø     Compared to FPM D-RAM EDO D-RAM provides 90% improvement in reading the data.

Ø     The improvement can be done by continuing to output data from one address while simultaneously setting up access request for next one.

Ø     This allows faster micro processor to manager the time more efficiently

SD-RAM: (Synchrony Data RAM)

Ø     It is designed to run at mother board clock speed . Synchronization the memory speed with CPU clock speed.

Ø     The speed of SD-RAM depends upon the CPU BUS.

Ø     It is faster then SD-RAM, D-RAM, and Memories.

Ø     It runs with an average speed of at 133MHz which is about three times faster than FPM RAM and twice as fast as EDO RAM. Most Pentium or Celeron systems purchased in 1999 have SDRAM.

DDR RAM

Ø     It is also Synchronization with system clock.

Ø     SD-RAM transfers data on rising edge of clock signal where as DDR transfers data on doth edges of clock signal

Ø     That’s why data transfer rate of DDR is faster then SD-RAM

Ø     It is almost twice the speed of SD-RAM.

RAMBUS DYNAMIC RAM:

Ø     IT has the clock speed of 800MHz

Ø     It has bus width of 2 bytes.

Ø     It can achieve speed up to 1.6 G bps.

SIMM:-

Ø     SIMM generally come in 30 pin (or)72 pin (or) 68 pin

Ø     It generally come in various capacities ranging from 512 KB.

Ø     IT supports 32 bit Date width RAM

Ø     It support  FPM,EDO

DIMM:-

Ø     It support 64 bit  date RAM

Ø     It has 168 pin SD-RAM.

Ø     It has 240 PIN DDR2

Ø     It has 184 PIN DDR1

Ø     It support  SD RAM,DDR1,DDR2,RDRAM

SODIMM :-( Small out Line)

Ø     It is use in Laptops computers.

SRAM	DRAM
Stores data till the power is switched off .	Stores data only for few milliseconds
Uses a set of transistors for each memory cell	Uses a single transistor and capacitor for each memory cell
Does not refresh the memory cell after each reading of the transistors.	Needs to refresh the memory cell after each reading of the capacitor
Data access is faster .	Data access is slower
Consumed more Power.	Consumed less power.
More expensive than DRAM.	Less expensive than SRAM.

RAM Specifications:

RAM  type	Pins	Width	Usage
SD RAM	168	64 bit	Older and slower type. No use.
Ram bus RAM	184	16 bit	Advanced RAM. Only used for very few Pentium 4’s with certain Intel chipsets.
DDR RAM	184	64 bit	A faster version of SD RAM. Used both for Athlon and Pentium 4’s. 2,5 Volt.
DDR2 RAM	240	64 bit	New version of DDR RAM with higher clock frequencies. 1,8 Volt.